Advanced Higher Maths · SQA past paper

2022 Paper 1

Non-Calculator · 8 questions
1(a)

Question 1(a)

Differentiation
3 Marks
2022 P1 Q1(a)

Given y=13xx2+4\displaystyle y = \frac{1-3x}{x^2+4}, find dydx.\displaystyle \frac{dy}{dx}. Simplify your answer.

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3x22x12(x2+4)2\displaystyle \frac{3x^2 - 2x - 12}{(x^2+4)^2}
1(b)

Question 1(b)

Differentiation
2 Marks
2022 P1 Q1(b)

Given f(x)=cosec 5x\displaystyle f(x) = \text{cosec } 5x, find f(x).\displaystyle f'(x).

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5cosec 5xcot5x\displaystyle -5\text{cosec } 5x \cot 5x
2

Question 2

Systems of Equations
4 Marks
2022 P1 Q2

Use Gaussian elimination to solve the following system of equations:

x2y+z=4\displaystyle x - 2y + z = 4
2x+y3z=3\displaystyle 2x + y - 3z = 3
x7y4z=9\displaystyle x - 7y - 4z = 9

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x=2,y=1,z=0\displaystyle x = 2, y = -1, z = 0
3

Question 3

Complex Numbers
2 Marks
2022 P1 Q3

Given that z1=5+3i\displaystyle z_1 = 5 + 3i and z2=6+2i\displaystyle z_2 = 6 + 2i, express z1z2\displaystyle z_1\overline{z_2} in the form a+ib\displaystyle a + ib where a\displaystyle a and b\displaystyle b are real numbers.

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36+8i\displaystyle 36 + 8i
4

Question 4

Differentiation
(3, 1, 2)6 Marks
2022 P1 Q4

A curve is defined by the equation y3+4y=2xy+1.\displaystyle y^3 + 4y = 2xy + 1.

(a)Use implicit differentiation to find an expression for dydx.\displaystyle \frac{dy}{dx}.

(b)Find the gradient of the tangent to the curve when y=1.\displaystyle y = -1.

(c)Show that the curve has no stationary point.

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(a) 2y3y2+42x\displaystyle \frac{2y}{3y^2 + 4 - 2x}
(b) 2\displaystyle -2
(c) Setting dydx=0\displaystyle \frac{dy}{dx} = 0 yields 2y=0y=0.\displaystyle 2y = 0 \Rightarrow y = 0. Substituting y=0\displaystyle y = 0 into the original equation gives 0=1\displaystyle 0 = 1, which is inconsistent. Therefore, there are no stationary points.
5

Question 5

Maclaurin Series
(2, 2)4 Marks
2022 P1 Q5

(a)Find, and simplify, the Maclaurin expansion for e4x\displaystyle e^{-4x} up to and including the term in x3.\displaystyle x^3.

(b)Hence find the first four terms of the Maclaurin expansion of 3+2xe4x.\displaystyle \frac{3+2x}{e^{4x}}.

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(a) 14x+8x2323x3\displaystyle 1 - 4x + 8x^2 - \frac{32}{3}x^3
(b) 310x+16x216x3\displaystyle 3 - 10x + 16x^2 - 16x^3
6

Question 6

Methods of Proof
(1, 3)4 Marks
2022 P1 Q6

Consider the statement: For all odd numbers n\displaystyle n, n2+4\displaystyle n^2 + 4 is prime.

(a)Find a counterexample to show that the statement is false.

(b)Prove directly that the difference between the cubes of any two consecutive integers is not divisible by 3.

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(a) e.g. when n=9\displaystyle n = 9, n2+4=85\displaystyle n^2 + 4 = 85, which is divisible by 5 and therefore not prime.
(b) Let the consecutive integers be n\displaystyle n and n+1.\displaystyle n+1. Then (n+1)3n3=3(n2+n)+1\displaystyle (n+1)^3 - n^3 = 3(n^2 + n) + 1, which leaves a remainder of 1 when divided by 3, so it is not divisible by 3.
7

Question 7

Integration
(4, 1, 1, 4)10 Marks
2022 P1 Q7

(a)Use the substitution u=y2+1\displaystyle u = y^2 + 1, or otherwise, to find the exact value of

054yy2+1dy.\displaystyle \int_0^5 \frac{4y}{\sqrt{y^2+1}} \,dy.

Student engineers are using a 3D printer to make a model. Relative to a suitable set of axes, the cross-section of the model is symmetrical about the y\displaystyle y-axis and is represented in the first quadrant by the curve x=4yy2+1\displaystyle x = \frac{4y}{\sqrt{y^2+1}}, 0y5.\displaystyle 0 \le y \le 5.

Curve of x = 4y / sqrt(y^2 + 1) bounding an area to the y-axis

(b)State the area of the cross-section.

(c)Express y2y2+1\displaystyle \frac{y^2}{y^2+1} in the form a+by2+1\displaystyle a + \frac{b}{y^2+1} where a\displaystyle a and b\displaystyle b are real numbers.

The curve x=4yy2+1\displaystyle x = \frac{4y}{\sqrt{y^2+1}}, 0y5\displaystyle 0 \le y \le 5 will be rotated through 2π\displaystyle 2\pi radians about the y\displaystyle y-axis to make the model.

(d)Find the volume of the model.

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(a) 4(261)\displaystyle 4(\sqrt{26} - 1)
(b) 8(261)\displaystyle 8(\sqrt{26} - 1) (square units)
(c) 11y2+1\displaystyle 1 - \frac{1}{y^2+1}
(d) 16π(5tan15)\displaystyle 16\pi(5 - \tan^{-1} 5) (cubic units)