Advanced Higher Maths · SQA past paper

2022 Paper 2

Calculator · 13 questions
1

Question 1

Partial Fractions
3 Marks
2022 P2 Q1

Express 3x23x+5x(x2+5)\displaystyle \frac{3x^{2}-3x+5}{x(x^{2}+5)} in partial fractions.

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1x+2x3x2+5\displaystyle \frac{1}{x} + \frac{2x-3}{x^{2}+5}
2

Question 2

Integration
2 Marks
2022 P2 Q2

Find the exact value of 0342x+1dx.\displaystyle \int_{0}^{3}\frac{4}{2x+1}dx.

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2ln7\displaystyle 2 \ln 7
3

Question 3

Number Theory
3 Marks
2022 P2 Q3

Use the Euclidean algorithm to find integers a\displaystyle a and b\displaystyle b such that 634a+87b=1.\displaystyle 634a+87b=1.

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a=7\displaystyle a = 7, b=51\displaystyle b = -51
4

Question 4

Integration
3 Marks
2022 P2 Q4

Use integration by parts to find (x+2)(2x+7)12dx.\displaystyle \int(x+2)(2x+7)^{\frac{1}{2}}dx.

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13(x+2)(2x+7)32115(2x+7)52+c\displaystyle \frac{1}{3}(x+2)(2x+7)^{\frac{3}{2}} - \frac{1}{15}(2x+7)^{\frac{5}{2}} + c
5

Question 5

Matrices
3 Marks
2022 P2 Q5

Matrix A\displaystyle A is given by A=(1312k3k187)\displaystyle A=\begin{pmatrix}1&3&1\\2&k&3\\k&18&-7\end{pmatrix}, where kR.\displaystyle k\in\mathbb{R}.
Find the values of k\displaystyle k so that the matrix A\displaystyle A is singular.

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6\displaystyle 6 and 4\displaystyle -4
6

Question 6

Sequences & Series
(2, 2, 2)6 Marks
2022 P2 Q6

The first three terms of a sequence are defined algebraically by x+5\displaystyle x+5, 3x+2\displaystyle 3x+2, 5x1\displaystyle 5x-1, where xN.\displaystyle x\in\mathbb{N}.

(a)Show that these three terms form the start of an arithmetic sequence.

(b)Find a simplified expression for the 15th\displaystyle 15^{th} term of this sequence.

(c)Given that the sum of the first 20 terms of this sequence is 1130, find the value of x.\displaystyle x.

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(a) (3x+2)(x+5)=2x3\displaystyle (3x+2) - (x+5) = 2x-3 and (5x1)(3x+2)=2x3.\displaystyle (5x-1) - (3x+2) = 2x-3. Common difference is the same, so it is arithmetic.
(b) 29x37\displaystyle 29x - 37
(c) x=4\displaystyle x = 4
7

Question 7

Complex Numbers
(1, 2, 1)4 Marks
2022 P2 Q7

The complex number z=3+i\displaystyle z=3+i is a root of z26z+a=0\displaystyle z^{2}-6z+a=0 where a\displaystyle a is a real number.

(a)State the second root of z26z+a=0.\displaystyle z^{2}-6z+a=0.

(b)Hence, or otherwise, find the value of a.\displaystyle a.

The expression z26z+a\displaystyle z^{2}-6z+a is a factor of z3z220z+b\displaystyle z^{3}-z^{2}-20z+b where b\displaystyle b is a real number.

(c)Find the value of b.\displaystyle b.

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(a) 3i\displaystyle 3 - i
(b) 10\displaystyle 10
(c) 50\displaystyle 50
8

Question 8

DifferentiationDifferential Equations
(2, 4)6 Marks
2022 P2 Q8

(a)Differentiate xlnxx\displaystyle x \ln x - x with respect to x.\displaystyle x.

(b)Hence find the general solution of the differential equation dydx+ylnx=xx.\displaystyle \frac{dy}{dx} + y \ln x = x^{-x}.

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(a) lnx\displaystyle \ln x
(b) y=ex+cxxex\displaystyle y = \frac{-e^{-x} + c}{x^{x}e^{-x}}
9

Question 9

Methods of ProofMatrices
5 Marks
2022 P2 Q9

The matrix A\displaystyle A is given by A=(3201).\displaystyle A=\begin{pmatrix}3&-2\\0&1\end{pmatrix}.
Prove by induction that An=(3n13n01),nN.\displaystyle A^{n}=\begin{pmatrix}3^{n}&1-3^{n}\\0&1\end{pmatrix}, \forall n\in \mathbb{N}.

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Proof by induction: show true for n=1\displaystyle n=1; assume true for n=k\displaystyle n=k; use Ak+1=AAk\displaystyle A^{k+1} = A \cdot A^k to show it holds for n=k+1.\displaystyle n=k+1. Conclude it is true nN.\displaystyle \forall n \in \mathbb{N}.
10

Question 10

Differential Equations
9 Marks
2022 P2 Q10

Solve the differential equation d2ydx24dydx+4y=9sinx+13cosx\displaystyle \frac{d^{2}y}{dx^{2}}-4\frac{dy}{dx}+4y=9 \sin x+13 \cos x given that y=5\displaystyle y=5 and dydx=0\displaystyle \frac{dy}{dx}=0 when x=0.\displaystyle x=0.

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y=2e2x3xe2xsinx+3cosx\displaystyle y = 2e^{2x} - 3xe^{2x} - \sin x + 3\cos x
11

Question 11

Differentiation
4 Marks
2022 P2 Q11

A curve defined parametrically has the following properties:
x=tan12t\displaystyle x = \tan^{-1} 2t
dydx=6t(1+4t2)\displaystyle \frac{dy}{dx} = 6t(1+4t^{2})
y=5\displaystyle y = 5 when t=1.\displaystyle t = 1.
Find y\displaystyle y in terms of t.\displaystyle t.

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y=6t21\displaystyle y = 6t^{2} - 1
12

Question 12

Complex NumbersBinomial Theorem
(1, 3, 2, 2)8 Marks
2022 P2 Q12

Let z=cosθ+isinθ.\displaystyle z = \cos \theta + i \sin \theta.

(a)Use de Moivre's theorem to state an expression for z4.\displaystyle z^{4}.

(b)State and simplify the binomial expansion of (cosθ+isinθ)4.\displaystyle (\cos \theta + i \sin \theta)^{4}.

(c)Hence show that:
(i) cos4θ=8cos4θ8cos2θ+1.\displaystyle \cos 4\theta = 8\cos^{4}\theta - 8\cos^{2}\theta + 1.
(ii) sinθcot4θ\displaystyle \sin \theta \cot 4\theta can be written in terms of cosθ\displaystyle \cos \theta only.

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(a) cos4θ+isin4θ\displaystyle \cos 4\theta + i \sin 4\theta
(b) cos4θ+4icos3θsinθ6cos2θsin2θ4icosθsin3θ+sin4θ\displaystyle \cos^{4}\theta + 4i \cos^{3}\theta \sin \theta - 6\cos^{2}\theta \sin^{2}\theta - 4i \cos \theta \sin^{3}\theta + \sin^{4}\theta
(c)(i) Equating real parts: cos4θ=cos4θ6cos2θsin2θ+sin4θ=8cos4θ8cos2θ+1\displaystyle \cos 4\theta = \cos^{4}\theta - 6\cos^{2}\theta \sin^{2}\theta + \sin^{4}\theta = 8\cos^{4}\theta - 8\cos^{2}\theta + 1
(c)(ii) 8cos4θ8cos2θ+18cos3θ4cosθ\displaystyle \frac{8\cos^{4}\theta - 8\cos^{2}\theta + 1}{8\cos^{3}\theta - 4\cos \theta}
13

Question 13

Differentiation
(1, 4, 1, 3)9 Marks
2022 P2 Q13

A security spotlight is situated 10 metres from a straight fence. The spotlight rotates at a constant speed and makes one full revolution every 12 seconds. L\displaystyle L is the spotlight, G\displaystyle G is the nearest point on the fence, P\displaystyle P is where the light hits the fence, θ\displaystyle \theta is the angle between LG\displaystyle LG and LP\displaystyle LP, and x\displaystyle x is the distance in metres from G\displaystyle G to P.\displaystyle P.

Spotlight pointing at a fence

(a)Show that:
(i) dθdt=π6\displaystyle \frac{d\theta}{dt} = \frac{\pi}{6} radians per second
(ii) dxdt=5π3sec2θ\displaystyle \frac{dx}{dt} = \frac{5\pi}{3}\sec^{2}\theta metres per second.

(b)Prove that 1+tan2θ=sec2θ.\displaystyle 1+\tan^{2}\theta=\sec^{2}\theta.

(c)Hence, or otherwise, find the exact value of dxdt\displaystyle \frac{dx}{dt} when P\displaystyle P is 5 metres from G.\displaystyle G.

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(a)(i) 2π12=π6\displaystyle \frac{2\pi}{12} = \frac{\pi}{6}
(a)(ii) x=10tanθ\displaystyle x = 10 \tan \theta, so dxdt=10sec2θπ6=5π3sec2θ\displaystyle \frac{dx}{dt} = 10\sec^{2}\theta \cdot \frac{\pi}{6} = \frac{5\pi}{3}\sec^{2}\theta
(b) 1+sin2θcos2θ=1cos2θ=sec2θ\displaystyle 1 + \frac{\sin^{2}\theta}{\cos^{2}\theta} = \frac{1}{\cos^{2}\theta} = \sec^{2}\theta
(c) 25π12 ms1\displaystyle \frac{25\pi}{12} \text{ ms}^{-1}