Advanced Higher Maths · SQA past paper

2024 Paper 1

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Question 1

Product, quotient, chain rules
(2, 2)4 Marks
2024 P1 Q1

Differentiate the following with respect to x\displaystyle x:

(a)y=cot⁡3x\displaystyle y = \cot 3x

(b)f(x)=5x(4x−7)12\displaystyle f(x) = 5x(4x - 7)^{\frac{1}{2}}

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(a) −3cosec⁡23x\displaystyle -3\operatorname{cosec}^2 3x
(b) 5(4x−7)12+10x(4x−7)−12\displaystyle 5(4x - 7)^{\frac{1}{2}} + 10x(4x - 7)^{-\frac{1}{2}}

Question 2

Argand diagramde Moivre's theorem
(2, 2)4 Marks
2024 P1 Q2

A complex number is defined by z=1+i.\displaystyle z = 1 + i.

(a)Express z\displaystyle z in polar form.

(b)Use de Moivre's theorem to evaluate z8.\displaystyle z^8.

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(a) 2(cos⁡π4+isin⁡π4)\displaystyle \sqrt{2}\left(\cos\frac{\pi}{4} + i\sin\frac{\pi}{4}\right)
(b) 16\displaystyle 16

Question 3

Geometric sequences and series
(2, 1, 1, 1)5 Marks
2024 P1 Q3

A geometric sequence of positive terms has third term 36 and fifth term 16.

(a)Calculate the value of the common ratio.

(b)Calculate the value of the first term.

(c)State why the associated geometric series has a sum to infinity.

(d)Find the value of this sum to infinity.

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(a) 23\displaystyle \frac{2}{3}
(b) 81\displaystyle 81
(c) Because ∣23∣<1\displaystyle |\frac{2}{3}| < 1 (or −1<23<1\displaystyle -1 < \frac{2}{3} < 1)
(d) 243\displaystyle 243

Question 4

Determinant and inverseMatrix operations
(2, 2)4 Marks
2024 P1 Q4

Matrix A\displaystyle A is defined by A=(61113).\displaystyle A = \begin{pmatrix} 6 & 1 \\ 11 & 3 \end{pmatrix}.

(a)Find A−1\displaystyle A^{-1}, the inverse of matrix A.\displaystyle A.

Matrix B\displaystyle B is defined by B=(−43−52).\displaystyle B = \begin{pmatrix} -4 & 3 \\ -5 & 2 \end{pmatrix}.

(b)Find the matrix M\displaystyle M such that AM=B.\displaystyle AM = B.

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(a) 17(3−1−116)\displaystyle \frac{1}{7}\begin{pmatrix} 3 & -1 \\ -11 & 6 \end{pmatrix}
(b) (−112−3)\displaystyle \begin{pmatrix} -1 & 1 \\ 2 & -3 \end{pmatrix}

Question 5

Odd and even functionsPoints of inflection
(2, 2)4 Marks
2024 P1 Q5

The function f(x)\displaystyle f(x) is defined by f(x)=x3−x\displaystyle f(x) = x^3 - x, x∈R.\displaystyle x \in \mathbb{R}.

(a)Determine whether f(x)\displaystyle f(x) is even, odd or neither.

(b)Show that the graph of y=f(x)\displaystyle y = f(x) has a point of inflection.

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(a) Odd (since f(−x)=−x3+x=−(x3−x)=−f(x)\displaystyle f(-x) = -x^3 + x = -(x^3 - x) = -f(x))
(b) f′′(x)=6x=0\displaystyle f''(x) = 6x = 0 at x=0.\displaystyle x = 0. Since f′′(x)>0\displaystyle f''(x) > 0 for x>0\displaystyle x > 0 and f′′(x)<0\displaystyle f''(x) < 0 for x<0\displaystyle x < 0, concavity changes, indicating a point of inflection.

Question 6

Transformation matrices
(1, 1, 2)4 Marks
2024 P1 Q6

(a)Find the 2×2\displaystyle 2 \times 2 matrix, A\displaystyle A, associated with a reflection in the x\displaystyle x-axis.

(b)Describe the transformation associated with the matrix B=(0110).\displaystyle B = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}.

(c)Find the 2×2\displaystyle 2 \times 2 matrix, C\displaystyle C, associated with a reflection in the x\displaystyle x-axis followed by the transformation associated with (0110).\displaystyle \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}.

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(a) (100−1)\displaystyle \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}
(b) Reflection in the line y=x.\displaystyle y = x.
(c) (0−110)\displaystyle \begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix}

Question 7

Implicit differentiation
(3, 3)6 Marks
2024 P1 Q7

A curve is defined by the equation x2y+4xy2=−32\displaystyle x^2y + 4xy^2 = -32, y>0.\displaystyle y > 0.

(a)Use implicit differentiation to find an expression for dydx.\displaystyle \frac{dy}{dx}.

The curve has only one stationary point.

(b)Find the coordinates of the stationary point.

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(a) −2xy−4y2x2+8xy\displaystyle \frac{-2xy - 4y^2}{x^2 + 8xy}
(b) (−4,2)\displaystyle (-4, 2)

Question 8

Integration by substitution
4 Marks
2024 P1 Q8

Use the substitution u=tan⁡2x\displaystyle u = \tan 2x to evaluate

∫0π8tan⁡2xcos⁡22x dx.\displaystyle \int_{0}^{\frac{\pi}{8}} \frac{\sqrt{\tan 2x}}{\cos^2 2x} \,dx.

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13\displaystyle \frac{1}{3}