Advanced Higher Maths · SQA past paper

2025 Paper 1

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Question 1

Binomial expansion
4 Marks
2025 P1 Q1

Use the binomial theorem to expand (1x−3x)4.\displaystyle \left(\frac{1}{x} - 3x\right)^4.
Simplify your answer.

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1x4−12x2+54−108x2+81x4\displaystyle \frac{1}{x^4} - \frac{12}{x^2} + 54 - 108x^2 + 81x^4

Question 2

Product, quotient, chain rules
3 Marks
2025 P1 Q2

Given f(x)=2x3+x3+2x\displaystyle f(x) = \frac{2x^3 + x}{3 + 2x}, find f′(x).\displaystyle f'(x). Simplify your answer.

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8x3+18x2+3(3+2x)2\displaystyle \frac{8x^3 + 18x^2 + 3}{(3 + 2x)^2}

Question 3

Complex number operations
2 Marks
2025 P1 Q3

Two complex numbers are defined as z=11+10i\displaystyle z = 11 + 10i and w=3−2i.\displaystyle w = 3 - 2i.
Find zw\displaystyle \frac{z}{w} in the form a+bi\displaystyle a + bi, where a,b∈R.\displaystyle a, b \in \mathbb{R}.

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1+4i\displaystyle 1 + 4i

Question 4

Matrix operationsDeterminant and inverse
(1, 2, 1, 2)6 Marks
2025 P1 Q4

Matrices A\displaystyle A and B\displaystyle B are defined by A=(−32 01)\displaystyle A = \begin{pmatrix} -3 & 2 \\\ 0 & 1 \end{pmatrix} and B=(22 5λ)\displaystyle B = \begin{pmatrix} 2 & 2 \\\ 5 & \lambda \end{pmatrix} where λ∈R.\displaystyle \lambda \in \mathbb{R}.

(a)Find 3A+2B.\displaystyle 3A + 2B.

(b)(i) Find A′B\displaystyle A'B, where A′\displaystyle A' is the transpose of A.\displaystyle A.

(b)(ii) Find an expression for the determinant of A′B.\displaystyle A'B.

(b)(iii) Determine the value of λ\displaystyle \lambda such that A′B\displaystyle A'B is singular.

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(a) (−510 103+2λ)\displaystyle \begin{pmatrix} -5 & 10 \\\ 10 & 3 + 2\lambda \end{pmatrix}
(b)(i) (−6−6 94+λ)\displaystyle \begin{pmatrix} -6 & -6 \\\ 9 & 4 + \lambda \end{pmatrix}
(b)(ii) −6(4+λ)−(−6)(9)\displaystyle -6(4 + \lambda) - (-6)(9) or 30−6λ\displaystyle 30 - 6\lambda
(b)(iii) λ=5\displaystyle \lambda = 5

Question 5

Simple integration
2 Marks
2025 P1 Q5

Find ∫11+4x2dx.\displaystyle \int \frac{1}{1 + 4x^2} dx.

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12tan⁡−1(2x)+c\displaystyle \frac{1}{2} \tan^{-1}(2x) + c

Question 6

AsymptotesPartial fractions (improper)
(2, 2)4 Marks
2025 P1 Q6

On a suitable domain a curve is given by the equation y=f(x)\displaystyle y = f(x), where
f(x)=x2+x+5x−2.\displaystyle f(x) = \frac{x^2 + x + 5}{x - 2}.

(a)Express f(x)\displaystyle f(x) in the form Ax+B+Cx−2\displaystyle Ax + B + \frac{C}{x - 2}, where A,B\displaystyle A, B and C\displaystyle C are constants.

(b)State the equations of the vertical and non-vertical asymptotes of the curve.

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(a) x+3+11x−2\displaystyle x + 3 + \frac{11}{x - 2}
(b) Vertical asymptote: x=2\displaystyle x = 2
Non-vertical asymptote: y=x+3\displaystyle y = x + 3

Question 7

Separable DE
5 Marks
2025 P1 Q7

Solve the differential equation

dydx=y2x−1\displaystyle \frac{dy}{dx} = \frac{y}{2x - 1}, x,y>1\displaystyle x, y > 1,

given that y=12\displaystyle y = 12 when x=5.\displaystyle x = 5. Express y\displaystyle y in terms of x.\displaystyle x.

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y=4(2x−1)12\displaystyle y = 4(2x - 1)^{\frac{1}{2}} (or y=42x−1\displaystyle y = 4\sqrt{2x - 1})

Question 8

Intersection of planesIntersection of line and plane
(4, 3, 2)9 Marks
2025 P1 Q8

Three planes are defined by

π1:x−y+4z=−6\displaystyle \pi_1:\quad x - y + 4z = -6
π2:2x+3y+z=15\displaystyle \pi_2:\quad 2x + 3y + z = 15
π3:3x+2y−2z=16\displaystyle \pi_3:\quad 3x + 2y - 2z = 16

(a)Use Gaussian elimination to find T, the point of intersection of the three planes.

The line L1\displaystyle L_1 is defined by x+43=y−72=z−41.\displaystyle \frac{x + 4}{3} = \frac{y - 7}{2} = \frac{z - 4}{1}.

(b)Find P, the point of intersection of the line L1\displaystyle L_1 and the plane π3.\displaystyle \pi_3.

The line L2\displaystyle L_2 passes through points T (the point of intersection of the three planes) and P (the point of intersection of the line L1\displaystyle L_1 and the plane π3\displaystyle \pi_3).

(c)Find, in parametric form, the equations of the line L2.\displaystyle L_2.

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(a) x=2,y=4,z=−1\displaystyle x = 2, y = 4, z = -1
(b) P(2,11,6)\displaystyle P(2, 11, 6)
(c) x=2,y=11+7λ,z=6+7λ\displaystyle x = 2, y = 11 + 7\lambda, z = 6 + 7\lambda (or equivalent)