Higher Maths · SQA past paper

2015 Paper 1

Non-Calculator · 15 questions
1

Question 1

Perpendicular vectors and the scalar product
2 Marks
2015 P1 Q1
Vectors
u=8i+2jk\displaystyle \mathbf{u}=8\mathbf{i}+2\mathbf{j}-\mathbf{k}
and
v=3i+tj6k\displaystyle \mathbf{v}=-3\mathbf{i}+t\mathbf{j}-6\mathbf{k}
are perpendicular.
Determine the value of t.\displaystyle t.
Show answer
t=9\displaystyle t=9
2

Question 2

Equation of a tangent to a curve
4 Marks
2015 P1 Q2
Find the equation of the tangent to the curve y=2x3+3\displaystyle y=2x^{3}+3 at the point where x=2.\displaystyle x=-2.
Show answer
y=24x+35\displaystyle y=24x+35
3

Question 3

Cubic/quartic expressions/equations: factorise or solve
4 Marks
2015 P1 Q3
Show that (x+3)\displaystyle (x+3) is a factor of x33x210x+24\displaystyle x^{3}-3x^{2}-10x+24 and hence factorise x33x210x+24\displaystyle x^{3}-3x^{2}-10x+24 fully.
Show answer
(x+3)(x4)(x2)\displaystyle (x+3)(x-4)(x-2)
4

Question 4

Identifying/sketching graphs of related functions (trigonometric)
3 Marks
2015 P1 Q4

The diagram shows part of the graph of the function y=pcosqx+r.\displaystyle y=p \cos qx+r.

Graph of y=p cos qx + r

Write down the values of p,q\displaystyle p, q and r.\displaystyle r.

Show answer
p=3,q=4,r=1\displaystyle p=3, q=4, r=1
5

Question 5

Inverse functions
(2, 1)3 Marks
2015 P1 Q5

A function g\displaystyle g is defined on R\displaystyle \mathbb{R}, the set of real numbers, by g(x)=62x\displaystyle g(x)=6-2x

(a)  Determine an expression for g1(x).\displaystyle g^{-1}(x).
(b)  Write down an expression for g(g1(x)).\displaystyle g(g^{-1}(x)).

Show answer
(a) g1(x)=6x2\displaystyle g^{-1}(x)=\frac{6-x}{2} or 3x2\displaystyle 3-\frac{x}{2}
(b) x\displaystyle x
6

Question 6

Simplify numerical expression involving logs/exponentials
3 Marks
2015 P1 Q6
Evaluate
log612+13log627\displaystyle \log_{6}12+\frac{1}{3}\log_{6}27
Show answer
2\displaystyle 2
7

Question 7

Differentiate or evaluate derivative: polynomial
4 Marks
2015 P1 Q7
A function f\displaystyle f is defined on a suitable domain by
f(x)=x(3x2xx)\displaystyle f(x)=\sqrt{x}(3x-\frac{2}{x\sqrt{x}})
Find f(4).\displaystyle f'(4).
Show answer
918\displaystyle 9\frac{1}{8} or 738\displaystyle \frac{73}{8} or 9.125\displaystyle 9.125
8

Question 8

Quadratic inequations
4 Marks
2015 P1 Q8

ABCD is a rectangle with sides of lengths x\displaystyle x centimetres and (x2)\displaystyle (x-2) centimetres, as shown.

Rectangle ABCD

If the area of ABCD is less than 15 cm2\displaystyle 15\text{ cm}^{2}, determine the range of possible values of x.\displaystyle x.

Show answer
2<x<5\displaystyle 2 \lt x \lt 5
9

Question 9

Angles and straight lines: m = tanθPerpendicular and parallel lines
3 Marks
2015 P1 Q9
A, B and C are points such that AB is parallel to the line with equation
y+3x=0\displaystyle y+\sqrt{3}x=0
and BC makes an angle of 150\displaystyle 150^{\circ} with the positive direction of the x-axis.
Are the points A, B and C collinear?
Show answer
No, they are not collinear.
10

Question 10

Apply double angle formula to simplify or evaluate
(1, 2)3 Marks
2015 P1 Q10

Given that tan2x=34\displaystyle \tan 2x=\frac{3}{4}
0<x<π4\displaystyle 0 \lt x \lt \frac{\pi}{4}
find the exact value of

(a)  cos2x.\displaystyle \cos 2x.
(b)  cosx.\displaystyle \cos x.

Show answer
(a) 45\displaystyle \frac{4}{5}
(b) 310\displaystyle \frac{3}{\sqrt{10}} or 31010\displaystyle \frac{3\sqrt{10}}{10}
11

Question 11

Equation of a tangent to a circle at a pointEquation of a tangent to a curve
(4, 6)10 Marks
2015 P1 Q11

T(2,5)\displaystyle T(-2,-5) lies on the circumference of the circle with equation
(x+8)2+(y+2)2=45\displaystyle (x+8)^{2}+(y+2)^{2}=45

(a)  Find the equation of the tangent to the circle passing through T.
(b)  This tangent is also a tangent to a parabola with equation
y=2x2+px+1p\displaystyle y=-2x^{2}+px+1-p
where p>3\displaystyle p \gt 3
Determine the value of p.\displaystyle p.

Show answer
(a) y=2x1\displaystyle y=2x-1
(b) p=10\displaystyle p=10
12

Question 12

Areas using integration
2 Marks
2015 P1 Q12

The diagram shows part of the graph of y=acosbx.\displaystyle y=a \cos bx. The shaded area is 12 unit2.\displaystyle \frac{1}{2}\text{ unit}^{2}.

Graph of y=a cos bx

What is the value of
03π4(acosbx)dx\displaystyle \int_{0}^{\frac{3\pi}{4}}(a \cos bx)dx?

Show answer
12\displaystyle -\frac{1}{2}
13

Question 13

Graphs of logarithmic or exponential functionsIdentifying/sketching graphs of related functions (non-trigonometric)
(1, 1, 3, 2)7 Marks
2015 P1 Q13

The function f(x)=2x+3\displaystyle f(x)=2^{x}+3
is defined on R\displaystyle \mathbb{R}, the set of real numbers.
The graph with equation y=f(x)\displaystyle y=f(x) passes through the point P(1,b)\displaystyle P(1,b) and cuts the y-axis at Q as shown in the diagram.

Exponential graph y=f(x)

(a)  What is the value of b\displaystyle b?

(b)  (i) Copy the above diagram. On the same diagram, sketch the graph with equation
y=f1(x)\displaystyle y=f^{-1}(x)

      (ii) Write down the coordinates of the images of P and Q.

(c)  R(3,11)\displaystyle R(3,11) also lies on the graph with equation y=f(x).\displaystyle y=f(x).
Find the coordinates of the image of R on the graph with equation
y=4f(x+1)\displaystyle y=4-f(x+1)

Show answer
(a) b=5\displaystyle b=5
(b) (ii) P'(5,1), Q'(4,0)
(c) (2, -7)
14

Question 14

Circle equation from radius/centre or vice versa
2 Marks
2015 P1 Q14
The circle with equation
x2+y212x10y+k=0\displaystyle x^{2}+y^{2}-12x-10y+k=0
meets the coordinate axes at exactly three points.
What is the value of k\displaystyle k?
Show answer
k=0\displaystyle k=0 or k=25\displaystyle k=25
15

Question 15

Differential equation
6 Marks
2015 P1 Q15

The rate of change of the temperature, TC\displaystyle T^{\circ}\text{C} of a mug of coffee is given by
dTdt=125tk\displaystyle \frac{dT}{dt}=\frac{1}{25}t-k, 0t50\displaystyle 0 \le t \le 50
•  t\displaystyle t is the elapsed time, in minutes, after the coffee is poured into the mug
•  k\displaystyle k is a constant
•  initially, the temperature of the coffee is 100C\displaystyle 100^{\circ}\text{C}
•  10 minutes later the temperature has fallen to 82C\displaystyle 82^{\circ}\text{C}

Express T\displaystyle T in terms of t.\displaystyle t.

Show answer
T=150t22t+100\displaystyle T = \frac{1}{50}t^2 - 2t + 100