Higher Maths · SQA past paper

2024 Paper 2

Calculator · 13 questions
1

Question 1

Altitudes, medians, perpendicular bisectorsIntersection of straight lines
(3, 3, 2)8 Marks
2024 P2 Q1

Triangle ABC has vertices A(3,8)\displaystyle A(-3,8), B(1,6)\displaystyle B(-1,-6) and C(11,0)\displaystyle C(11,0).

Triangle ABC with median and perpendicular line

(a)  Find the equation of the median through B.
(b)  Find the equation of L, the line perpendicular to BC passing through C.
(c)  Determine the coordinates of the point of intersection of the median through B and the line L.

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(a) y=2x4\displaystyle y=2x-4
(b) y=2x+22\displaystyle y=-2x+22
(c) (132,9)\displaystyle (\frac{13}{2}, 9) or (6.5, 9)
2

Question 2

Equation of a tangent to a curve
5 Marks
2024 P2 Q2

A curve has equation
y=8x3\displaystyle y=\frac{8}{x^{3}}
where x>0.\displaystyle x \gt 0.
Find the equation of the tangent to this curve at the point where x=2\displaystyle x=2.

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3x+2y=8\displaystyle 3x+2y=8 or y=32x+4\displaystyle y=-\frac{3}{2}x+4
3

Question 3

Calculating an angle using the scalar productScalar product
(2, 1, 4)7 Marks
2024 P2 Q3

The coordinates of points D, E and F are given by D(2,3,4)\displaystyle D(2,-3,4), E(1,1,2)\displaystyle E(1,1,-2) and F(3,2,1).\displaystyle F(3,2,1).
(a)  Express ED\displaystyle \overrightarrow{ED} and EF\displaystyle \overrightarrow{EF} in component form.
(b)  (i) Calculate ED.EF.\displaystyle \overrightarrow{ED}.\overrightarrow{EF}.
      (ii) Hence, or otherwise, calculate the size of angle DEF.

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(a) ED=(146)\displaystyle \overrightarrow{ED}=\begin{pmatrix}1\\ -4\\ 6\end{pmatrix}, EF=(213)\displaystyle \overrightarrow{EF}=\begin{pmatrix}2\\ 1\\ 3\end{pmatrix}
(b) (i) 16 (ii) 54.0° or 0.943 rad
4

Question 4

Identifying/sketching graphs of related functions (non-trigonometric)The graph of the derived function
(2, 3)5 Marks
2024 P2 Q4

The diagram shows the graph of a quartic function y=f(x)\displaystyle y=f(x).
A maximum turning point occurs at (-1, 3).
The graph of y=f(x)\displaystyle y=f(x) also has a point of inflection at x=2\displaystyle x=2.

Graph of quartic function y=f(x)

(a)  Determine the coordinates of the maximum turning point on the graph of y=f(x4)+2\displaystyle y=f(x-4)+2.
(b)  On the diagram in your answer booklet, sketch the graph of y=f(x)\displaystyle y=f^{\prime}(x).

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(a) (3, 5)
(b) Sketch showing cubic curve with roots at x = -1 and x = 2 (touching axis)
5

Question 5

Integrate (definite or indefinite): trigonometric expression
3 Marks
2024 P2 Q5

Evaluate
0π7sin5xdx\displaystyle \int_{0}^{\frac{\pi}{7}}\sin 5x dx

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0.325 (to 3 d.p.)
6

Question 6

Deriving relationship y = ab^x or y = ax^b from straight line
5 Marks
2024 P2 Q6

Two variables, x and y, are connected by the equation y=axb\displaystyle y=ax^{b}.
The graph of log5y\displaystyle \log_{5}y against log5x\displaystyle \log_{5}x is a straight line as shown.

Graph of log5y against log5x

Find the values of a and b.

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a=125,b=3\displaystyle a=\frac{1}{25}, b=3
7

Question 7

Areas using integration
5 Marks
2024 P2 Q7

The diagram shows the curve with equation y=x36x2+11x\displaystyle y=x^{3}-6x^{2}+11x intersecting the curve with equation y=6+4x2x2\displaystyle y=6+4x-2x^{2} at x=2\displaystyle x=2

Intersection of cubic and quadratic curves

Calculate the shaded area.

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143\displaystyle \frac{14}{3} or 423\displaystyle 4\frac{2}{3}
8

Question 8

Composite functionsDomain and range
(2, 2)4 Marks
2024 P2 Q8

Functions f and g are defined on R\displaystyle \mathbb{R}, the set of real numbers, by:
f(x)=2x218\displaystyle f(x)=2x^{2}-18
g(x)=x+1\displaystyle g(x)=x+1
(a)  Find an expression for f(g(x)).\displaystyle f(g(x)).
(b)  Find the values of x for which
1f(g(x))\displaystyle \frac{1}{f(g(x))}
is undefined.

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(a) 2(x+1)218\displaystyle 2(x+1)^{2}-18
(b) x=4,x=2\displaystyle x=-4, x=2
9

Question 9

Find stationary points and determine natureOptimisation on a closed interval
(4, 2)6 Marks
2024 P2 Q9

(a)  Determine the coordinates of the stationary points on the curve with equation
y=13x3x23x+1\displaystyle y=\frac{1}{3}x^{3}-x^{2}-3x+1
(b)  Hence, determine the greatest and least values of y in the interval 1x6\displaystyle -1\le x\le6.

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(a) (1,83)\displaystyle (-1, \frac{8}{3}) and (3,8)\displaystyle (3, -8)
(b) Greatest = 19, Least = -8
10

Question 10

Circle equation from radius/centre or vice versaIntersections of two circles
(2, 2)4 Marks
2024 P2 Q10

The circle C1\displaystyle C_{1} has equation x2+y2+18x2y8=0\displaystyle x^{2}+y^{2}+18x-2y-8=0.
(a)  Find the centre and radius of C1.\displaystyle C_{1}.
A second circle, C2,\displaystyle C_{2}, touches C1\displaystyle C_{1} internally.
The centre of C2\displaystyle C_{2} is (-6, 0).

Two circles touching internally

(b)  Determine the equation of C2\displaystyle C_{2}.

Show answer
(a) Centre (-9, 1), Radius 90\displaystyle \sqrt{90} or 310\displaystyle 3\sqrt{10}
(b) (x+6)2+y2=40\displaystyle (x+6)^{2}+y^{2}=40
11

Question 11

Solving equations where the unknown is in the exponent
(1, 4)5 Marks
2024 P2 Q11

The number of electric vehicles worldwide can be modelled by
N=6.8ekt\displaystyle N=6.8e^{kt}
where:
•  N is the estimated number of vehicles in millions
•  t is the number of years since the end of 2020
•  k is a constant.
(a)  Use the model to estimate the number of electric vehicles worldwide at the end of 2020.
At the end of 2030, it is estimated there will be 125 million electric vehicles worldwide.
(b)  Determine the value of k.

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(a) 6.8 million
(b) 0.291 (to 3 s.f.)
12

Question 12

Solving a trigonometric equation using formula for sin(2x)
5 Marks
2024 P2 Q12
Solve the equation
2sin2xsin2x=0\displaystyle 2 \sin 2x^{\circ}-\sin^{2}x^{\circ} = 0
for 0x<360\displaystyle 0\le x \lt 360.
Show answer
x=0,76.0,180,256.0\displaystyle x = 0, 76.0, 180, 256.0
13

Question 13

Identify polynomial equation when shown graph/roots
3 Marks
2024 P2 Q13

The diagram shows the graph of y=f(x)\displaystyle y=f(x), where f(x)\displaystyle f(x) is a quartic function.

Graph of quartic function f(x)

Express f(x)\displaystyle f(x) in the form
f(x)=k(x+a)2(x+b)(x+c)\displaystyle f(x)=k(x+a)^{2}(x+b)(x+c)

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f(x)=15(x+1)(x3)2(x5)\displaystyle f(x)=\frac{1}{5}(x+1)(x-3)^{2}(x-5)