Recurrence Relations · Guided Practice
Recurrence Relations
15 questions with answers and video solutions. Try each one before revealing the answer.
Given and find the value of and the value of
Find the values of and
Hence find the value of the fourth term in the sequence.
Given and find the value of and the value of
Explain why this sequence approaches a limit as and calculate this limit.
Answer
(a) State the values of and
(b) Explain whether or not the population will stabilise in the long term.
(c) The population at the beginning of the reintroduction programme was estimated at Explain whether or not the population will ever exceed
Answer
(b) Stabilises because
(c) No, because the limit is approximately
(a) Show that
(b) Find the range of values of for which
Answer
Find the range of values of for which such a sequence converges to a limit.
A sequence is defined by the recurrence relation
with
(a) Find the value of
(b) Explain why this sequence approaches a limit as
(c) Calculate this limit.
Answer
(b) A limit exists because
(c) 15
A sequence is generated by the recurrence relation
where is a constant.
(a) Given and , find the value of .
(b) (i) Explain why this sequence approaches a limit as .
(ii) Calculate this limit.
Answer
(b) Limit is 8
A sequence is generated by the recurrence relation , where the first three terms of the sequence are 6, 9 and 11.
(a) Find the values of and
(b) Hence, calculate the fourth term of the sequence.
Answer
(b) (or )
(a) Determine the value of
(b) Determine the limit of this sequence.
Answer
(b) Limit
Determine, algebraically, the value of
A sequence is defined by the recurrence relation
with
(a) Calculate the value of
(b) (i) Explain why this sequence approaches a limit as .
(ii) Calculate this limit.
Answer
(b) (i) A limit exists because (ii)
A sequence satisfies the recurrence relation , where m is a constant.
(a) The sequence approaches a limit of 10 as Determine the value of m.
(b) Given that , calculate the value of
Answer
(b)
A sequence is defined by the recurrence relation ,
(a) Calculate the value of
(b) Explain why this sequence does not approach a limit as
(c) Determine the smallest value of n for which
Answer
(b) A limit exists only when Here , which is greater than 1, so the sequence diverges and has no limit.
(c)
Practice questions courtesy of Maths.scot. Full written solutions are on his site — the links above go straight to them.