Introduction, Domain & Range0%

Functions & Graphs · Topic 1 of 9

Introduction, Domain & Range

Video lesson · from 4:42

One lesson video covers all of Functions & Graphs, so it opens at 4:42 for this topic — not from the beginning.

Theory

Introduction To Functions & Sets

A function is a rule which connects one set of numbers to another.

A function can be expressed in the following forms:

  • Table
  • Graph
  • Arrow diagram
  • Formula

Notation

f(x)=f(x) = \dots i.e. f of x

g(u)=g(u) = \dots i.e. g of u

A function is a relation between two sets where each member of the first set is related to only one member of the second set.

Domain of a Function

The domain of a function is the set of all possible input values (x-values) for which the function is defined.

Division by Zero

Since we cannot divide any number by zero, the domains of functions involving fractions must exclude numbers which would result in a denominator of zero.

f(x)=3x    x0f(x) = \frac{3}{x} \implies x \neq 0

f(x)=210x    x10f(x) = \frac{2}{10-x} \implies x \neq 10

f(x)=2x+1x24x    x0,x4f(x) = \frac{2x+1}{x^2-4x} \implies x \neq 0, x \neq 4

Even Roots

We cannot evaluate an even root of a negative number. The domain must exclude numbers which would result in negative numbers under the root.

f(x)=x    x0f(x) = \sqrt{x} \implies x \geq 0

f(x)=x4    x4f(x) = \sqrt{x-4} \implies x \geq 4

f(x)=2x+1x4    x>4f(x) = \frac{2x+1}{\sqrt{x-4}} \implies x > 4

Range of a Function

The range of a function is the spread of possible y-values (outputs).

FunctionRange
f(x)=cosxf(x) = \cos x1f(x)1-1 \leq f(x) \leq 1
f(x)=x2+4f(x) = x^2 + 4f(x)4f(x) \geq 4
f(x)=xf(x) = \sqrt{x}f(x)0f(x) \geq 0
f(x)=x2f(x) = \sqrt{x} - 2f(x)2f(x) \geq -2
f(x)=x3f(x) = x^3f(x)Rf(x) \in \mathbb{R}

⚠️ Common Examiner Traps

  • State the condition, not just the domain. Marks are routinely lost by giving the domain without saying why it is restricted. Name the value that breaks it: a denominator of zero, or a negative under a square root.
  • Denominators: for f(x)=1x3f(x) = \frac{1}{x-3} the function is undefined at x=3x = 3, so the domain is all real xx except 3. Set the denominator equal to zero to find it.
  • Square roots: for g(x)\sqrt{g(x)} you need g(x)0g(x) \geq 0 — solve that inequality rather than guessing.
  • Domain is inputs, range is outputs: writing one when the question asks for the other loses the mark even when the numbers are right.