Change of subject0%

Algebra · Topic 8 of 12

Change of subject

Video lesson5 worked examples

Theory

Changing the subject involves algebraically rearranging a formula to isolate a different variable.

This applies to linear formulas, as well as those involving simple squares or square roots.

You are expected to apply this to real-life contexts using formulae from science, health, and finance (e.g., E=12mv2E = \frac{1}{2}mv^2 or calculating the radius of a sphere given its volume).

The Golden Rule: use inverse operations to peel away everything around the target variable, in reverse order (undo +/+/- before ×/÷\times/\div, and undo those before powers/roots). To undo a square, take a root; to undo a root, square both sides. If the target appears in two terms, factorise it out first.

⚠️ Common Examiner Traps

  • Undoing in the wrong order: reverse the order of operations — deal with terms added or subtracted before multiplying or dividing.
  • Clearing a fraction: if the subject is trapped in a fraction, multiply both sides by the denominator first.
  • Roots and squares: to free a variable under a square root, square both sides; to free a squared variable, square-root both sides.
  • Subject in two terms: if the target appears twice (e.g. ax+bxax + bx), you must factorise it out — x(a+b)x(a + b) — before you can divide.

Worked examples

Example 1

Linear Formula

Change the subject of P=2L+2BP = 2L + 2B to L.

Step 1: Subtract 2B from both sides: P2B=2LP - 2B = 2L.

Step 2: Divide both sides by 2. Answer: L=P2B2L = \dfrac{P - 2B}{2}.

Example 2

Freeing a Squared Variable

Change the subject of A=πr2A = \pi r^2 to r.

Step 1: Divide by π\pi: Aπ=r2\dfrac{A}{\pi} = r^2.

Step 2: Undo the square by taking the square root of both sides. Answer: r=Aπr = \sqrt{\dfrac{A}{\pi}}.

Example 3

Subject in a Fraction

Change the subject of T=2a+5bT = \dfrac{2a + 5}{b} to a.

Step 1: The subject is trapped in a fraction, so multiply both sides by bb first: Tb=2a+5Tb = 2a + 5.

Step 2: Subtract 5 from both sides: Tb5=2aTb - 5 = 2a.

Step 3: Divide by 2. Answer: a=Tb52a = \dfrac{Tb - 5}{2}.

Example 4

Freeing a Variable Under a Root

Change the subject of y=3x+1y = \sqrt{3x + 1} to x.

Step 1: The xx is trapped under a square root, so undo it by squaring both sides: y2=3x+1y^2 = 3x + 1.

Step 2: Subtract 1 from both sides: y21=3xy^2 - 1 = 3x.

Step 3: Divide by 3. Answer: x=y213x = \dfrac{y^2 - 1}{3}.

Example 5

🔗 Bringing it together

Change the subject of ax+bx=cax + bx = c to x.

Step 1: The subject xx appears in two terms, so it cannot be isolated by dividing yet. Factorise it out:

x(a+b)=cx(a + b) = c

Step 2: Now xx is a single factor — divide both sides by the bracket:

Answer: x=ca+bx = \dfrac{c}{a + b}.