Differentiating Terms (Positive, Negative & Fractional Indices)0%

Differentiation · Topic 2 of 15

Differentiating Terms (Positive, Negative & Fractional Indices)

Video lesson · from 7:125 worked examples

One lesson video covers all of Differentiation, so it opens at 7:12 for this topic — not from the beginning.

Theory

Rather than using first principles every time, we can use a general rule for polynomials.

General Rule

If f(x)=xnf(x) = x^n then f(x)=nxn1(nR)f'(x) = nx^{n-1} \quad (n \in \mathbb{R})

Multiply by the power, reduce the power by 1.

This rule applies to positive, negative, and fractional indices.

⚠️ Common Examiner Traps

  • Negative indices: negative indices are the most reliable source of dropped marks in differentiation. Reducing the power by 1 makes it more negative — x2x^{-2} differentiates to 2x3-2x^{-3}, not 2x1-2x^{-1}.
  • Rewrite before you differentiate: the power rule only works on terms in the form axnax^n. Roots and fractions must be written as indices first.
  • Consistent lines of working: differentiation is a place where each line must follow logically from the one above. Do not collapse several steps into one line.
  • Simplify the final answer: an unsimplified derivative can cost the final mark even when the differentiation is perfect.

Worked examples

Example 1

A function ff is defined for xRx \in \mathbb{R} by f(x)=x4f(x) = x^4. Find f(x)f'(x).

f(x)=x4f(x)=4x3\begin{aligned} f(x) &= x^4 \\ f'(x) &= 4x^3 \end{aligned}

Example 2

A function ff is defined for xRx \in \mathbb{R} by f(x)=2x3f(x) = 2x^3. Find f(x)f'(x).

f(x)=2x3f(x)=6x2\begin{aligned} f(x) &= 2x^3 \\ f'(x) &= 6x^2 \end{aligned}

Example 3

Find f(x)f'(x) if f(x)=x3f(x) = x^{-3}.

f(x)=x3f(x)=3x4\begin{aligned} f(x) &= x^{-3} \\ f'(x) &= -3x^{-4} \end{aligned}

Example 4

Find f(x)f'(x) if f(x)=4x2f(x) = 4x^{-2}.

f(x)=4x2f(x)=8x3\begin{aligned} f(x) &= 4x^{-2} \\ f'(x) &= -8x^{-3} \end{aligned}

Example 5

Find f(x)f'(x) if f(x)=x13f(x) = x^{-\frac{1}{3}}.

f(x)=x13f(x)=13x43\begin{aligned} f(x) &= x^{-\frac{1}{3}} \\ f'(x) &= -\frac{1}{3}x^{-\frac{4}{3}} \end{aligned}