Preparing to Differentiate 2 – Indices0%

Differentiation · Topic 4 of 15

Preparing to Differentiate 2 – Indices

Video lesson · from 7:125 worked examples

One lesson video covers all of Differentiation, so it opens at 7:12 for this topic — not from the beginning.

Theory

Before differentiating, rewrite roots as fractional indices (xmn=xmn\sqrt[n]{x^m} = x^{\frac{m}{n}}).

Move variables out of the denominator to the numerator using negative indices (1xn=xn\frac{1}{x^n} = x^{-n}).

⚠️ Common Examiner Traps

  • Rewrite roots as fractional indices: x=x1/2\sqrt{x} = x^{1/2} and x23=x2/3\sqrt[3]{x^2} = x^{2/3}. You cannot apply the power rule until every term is in the form axnax^n.
  • Subtracting 1 from a fraction: 121=12\tfrac{1}{2} - 1 = -\tfrac{1}{2}, so x1/2x^{1/2} differentiates to 12x1/2\tfrac{1}{2}x^{-1/2}. This is a very common slip.
  • Negative indices go more negative: x3x^{-3} differentiates to 3x4-3x^{-4}. Negative indices are the most reliable source of dropped marks in this topic.
  • Match the form of the question: if it was asked with roots, it is usually best to give the answer with roots too.

Worked examples

Example 1

Differentiate x\sqrt{x} with respect to xx.

y=x12dydx=12x12=12x12=12x\begin{aligned} y &= x^{\frac{1}{2}} \\ \frac{dy}{dx} &= \frac{1}{2}x^{-\frac{1}{2}} \\ &= \frac{1}{2x^{\frac{1}{2}}} \\ &= \frac{1}{2\sqrt{x}} \end{aligned}

Example 2

Find the derivative of y=1x2y = \frac{1}{x^2} with respect to xx.

y=x2dydx=2x3=2x3\begin{aligned} y &= x^{-2} \\ \frac{dy}{dx} &= -2x^{-3} \\ &= -\frac{2}{x^3} \end{aligned}

Example 3

Differentiate y=2xy = \frac{2}{x} with respect to xx.

y=2x1dydx=2x2=2x2\begin{aligned} y &= 2x^{-1} \\ \frac{dy}{dx} &= -2x^{-2} \\ &= -\frac{2}{x^2} \end{aligned}

Example 4

Find the derivative of y=12xy = \frac{1}{2x} with respect to xx.

y=12x1dydx=12x2=12x2\begin{aligned} y &= \frac{1}{2}x^{-1} \\ \frac{dy}{dx} &= -\frac{1}{2}x^{-2} \\ &= -\frac{1}{2x^2} \end{aligned}

Example 5

Differentiate 32x\frac{3}{2\sqrt{x}} with respect to xx.

y=32x12=32x12dydx=1232x32=34x32=34x3\begin{aligned} y &= \frac{3}{2x^{\frac{1}{2}}} \\ &= \frac{3}{2}x^{-\frac{1}{2}} \\ \frac{dy}{dx} &= -\frac{1}{2} \cdot \frac{3}{2}x^{-\frac{3}{2}} \\ &= -\frac{3}{4}x^{-\frac{3}{2}} \\ &= -\frac{3}{4\sqrt{x^3}} \end{aligned}