Midpoints0%

The Straight Line · Topic 2 of 9

Midpoints

Video lesson · from 7:572 worked examples

One lesson video covers all of The Straight Line, so it opens at 7:57 for this topic — not from the beginning.

Theory

The midpoint is the exact centre point of a straight line connecting two points.

The midpoint of (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is found by averaging the xx and yy coordinates:

Midpoint=(x1+x22,y1+y22)\text{Midpoint} = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

⚠️ Common Examiner Traps

  • Add then divide, do not subtract: the midpoint averages the coordinates. Using the difference gives the length, not the middle.
  • Working backwards is common: given one endpoint and the midpoint, use x2=2xmx1x_2 = 2x_m - x_1. Guessing rarely works with negatives.
  • Careful with negatives: the average of 3-3 and 77 is 22. Write the addition down rather than doing it mentally.
  • Answer as coordinates: a midpoint is a point, so give it as a pair.

Worked examples

Example 1

Calculate the midpoint of (1,4)(1, -4) and (7,8)(7, 8).

M=(1+72,4+82)M = \left(\frac{1+7}{2}, \frac{-4+8}{2}\right)
M=(82,42)M = \left(\frac{8}{2}, \frac{4}{2}\right)
M=(4,2)M = (4, 2)

Example 2

In the diagram, A(9,2)A(9, -2) lies on the circumference of the circle with centre C(17,12)C(17, 12), and the line ABAB is the diameter of the circle. Find the co-ordinates of BB.

ACB

Since CC is the centre and ABAB is the diameter, CC is the midpoint of ABAB.

Let B=(x,y)B = (x, y).

9+x2=17    9+x=34    x=25\frac{9+x}{2} = 17 \implies 9+x = 34 \implies x = 25
2+y2=12    2+y=24    y=26\frac{-2+y}{2} = 12 \implies -2+y = 24 \implies y = 26

The co-ordinates of BB are (25,26)(25, 26).