Perpendicular Bisectors0%

The Straight Line · Topic 6 of 9

Perpendicular Bisectors

Video lesson · from 32:021 worked example

One lesson video covers all of The Straight Line, so it opens at 32:02 for this topic — not from the beginning.

Theory

Perpendicular

At right angles

Bisector

A line which divides another line into two equal parts.

i.e. a line which cuts through the midpoint of another line.

Perpendicular Bisector

A line which divides another line into two equal parts at right angles.

i.e. a line which cuts through the midpoint of another line at right angles.

ABCDABCED

To find the equation:

  1. Find the midpoint of the line.
  2. Find the gradient of the line.
  3. Find the perpendicular gradient (m1m2=1m_1 m_2 = -1).
  4. Use yb=m(xa)y - b = m(x - a) with the midpoint and perpendicular gradient.

The three perpendicular bisectors of a triangle meet at the circumcentre.

The circumcentre is the centre of the triangle's circumcircle which passes through all vertices of the triangle.

Circumcentre

⚠️ Common Examiner Traps

  • Two steps, both needed: the midpoint of the line and the perpendicular gradient. Missing either one is the usual way marks are lost.
  • Perpendicular means negative reciprocal: flip the fraction and change the sign — doing only one of the two is the classic error.
  • Use the midpoint in the equation: yb=m(xa)y - b = m(x - a) takes the midpoint, not either original endpoint.
  • Set the working out in order: midpoint, then original gradient, then perpendicular gradient, then equation. Each line should follow from the one above.

Worked examples

Example 1

A is the point (2,1)(-2, 1) and B is the point (4,7)(4, 7). Find the equation of the perpendicular bisector of AB.

1. Midpoint of AB:

M=(2+42,1+72)=(1,4)\begin{aligned} M &= \left(\frac{-2+4}{2}, \frac{1+7}{2}\right) \\ &= (1, 4) \end{aligned}

2. Gradient of AB:

mAB=714(2)=66=1\begin{aligned} m_{AB} &= \frac{7 - 1}{4 - (-2)} \\ &= \frac{6}{6} \\ &= 1 \end{aligned}

3. Perpendicular Gradient:

m=1m_{\perp} = -1

4. Equation:

y4=1(x1)y - 4 = -1(x - 1)
y4=x+1y - 4 = -x + 1
y=x+5 or x+y5=0y = -x + 5 \text{ or } x + y - 5 = 0