Volume0%

Geometry · Topic 3 of 8

Volume

Video lesson3 worked examples

Theory

You must be able to calculate the volume of standard solids:

  • Sphere (V=43πr3V = \frac{4}{3}\pi r^3)
  • Cone (V=13πr2hV = \frac{1}{3}\pi r^2 h)
  • Pyramid (V=13AhV = \frac{1}{3}Ah)
  • Cylinder (V=πr2hV = \pi r^2 h)
  • Prism (V=AhV = Ah)

Complex problems will require calculating the volume of composite solids (shapes joined together) or simple fractional parts of solids (e.g., hemispheres).

The Golden Rule: choose the right formula, and check whether you are given the radius or the diameter. For a composite solid, add the parts (or subtract, if one is removed). If the volume is given and a length is unknown, substitute and rearrange.

⚠️ Common Examiner Traps

  • Diameter given, not radius: if told the diameter, halve it first — a very common lost mark.
  • The 13\frac{1}{3} for cones and pyramids: forgetting it triples the answer.
  • Units: volume is in cubic units (cm³, m³); make sure all lengths are in the same unit before calculating.
  • Rounding: if asked for a number of significant figures, keep full accuracy until the end.

Worked examples

Example 1

Volume of a Cone

A cone has a base radius of 6 cm and a height of 14 cm. Calculate its volume.

Step 1: Substitute into the formula: V=13×π×62×14V = \frac{1}{3} \times \pi \times 6^2 \times 14.

Step 2: Calculate: 13×π×36×14=12×14×π\frac{1}{3} \times \pi \times 36 \times 14 = 12 \times 14 \times \pi.

Answer: 168π168\pi cm3 (or approx. 527.79 cm3).

Example 2

Composite Solid (Hemisphere + Cylinder)

A silo is formed by a cylinder of radius 4 m and height 10 m, topped by a hemisphere of the same radius. Find the total volume.

Step 1: Cylinder volume: V1=π×42×10=160πV_1 = \pi \times 4^2 \times 10 = 160\pi.

Step 2: Hemisphere volume: V2=12×(43π×43)=12×256π3=128π3V_2 = \frac{1}{2} \times (\frac{4}{3}\pi \times 4^3) = \frac{1}{2} \times \frac{256\pi}{3} = \frac{128\pi}{3}.

Step 3: Add them together: 160π+42.67π160\pi + 42.67\pi.

Answer: 202.67π\pi m3 (or approx. 636.70 m3).

Example 3

Working Backwards (finding a length)

A pyramid has a square base of side 6 cm and a volume of 96 cm³. Calculate its height.

Step 1: The base area is 6×6=366 \times 6 = 36 cm². Substitute the known values into V=13AhV = \frac{1}{3}Ah:

96=13×36×h96 = \frac{1}{3} \times 36 \times h

Step 2: Simplify the right-hand side: 96=12h96 = 12h.

Step 3: Divide to find hh: h=8h = 8.

Answer: the height is 8 cm.